Build mod_perl without pedantic flags even when debugging

This means we don't have to set PERL_GCC_PEDANTIC which removes
assertions that are helpful for debugging.

src/mod/languages/mod_perl/Makefile.am

@@ -3,13 +3,14 @@ MODNAME=mod_perl
 PERL        = perl
 PERL_LIBDIR =-L`perl -MConfig -e 'print $$Config{archlib}'`/CORE
 PERL_LIBS   =`perl -MConfig -e 'print $$Config{libs}'`
+CFLAGS_FILTER := -ansi -pedantic
 
 perldir=$(prefix)/perl
 mod_LTLIBRARIES = mod_perl.la
 perl_LTLIBRARIES = freeswitch.la
 mod_perl_la_SOURCES  = mod_perl.c freeswitch_perl.cpp mod_perl_wrap.cpp perlxsi.c
-mod_perl_la_CFLAGS   = $(AM_CFLAGS) -w
-mod_perl_la_CXXFLAGS   = $(AM_CXXFLAGS) -w
+mod_perl_la_CFLAGS   = $(filter-out $(CFLAGS_FILTER),$(AM_CFLAGS)) -w
+mod_perl_la_CXXFLAGS = $(filter-out $(CFLAGS_FILTER),$(AM_CXXFLAGS)) -w
 mod_perl_la_CPPFLAGS = -DMULTIPLICITY `$(PERL) -MExtUtils::Embed -e ccopts` -DEMBED_PERL -I$(switch_srcdir)/libs/libteletone/src/ 
 mod_perl_la_LIBADD   = $(switch_builddir)/libfreeswitch.la
 mod_perl_la_LDFLAGS  = -avoid-version -module -no-undefined -shared `$(PERL) -MExtUtils::Embed -e ldopts` `$(PERL) -MConfig -e 'print $$Config{libs}'`